XXV. The findings of Oxfam India’s latest ‘India Discrimination Report 2022’ indicate that there is a significant gap in the earnings between men and women in the case of regular and self-employment in urban areas. The lower wages for salaried women are due to 67 percent of discrimination and 33 percent due to lack of education and work experience. The average earning is ₹16000 for men and merely ₹6600 for women in urban areas in self-employment. The average earning of men is ₹19800 as against ₹15600 for women in regular/salaried employment in urban areas. Also, in urban areas the average earnings of men (₹9000) are significantly higher than women (₹5700) even in casual employment. Apart from women, historically oppressed communities along with religious minorities also continue to face discrimination in accessing jobs, livelihoods, and agricultural credit. The mean income for Scheduled Castes or Scheduled Tribes (“SC/ST”) persons in urban areas who are in regular employment is ₹15300 as against ₹20300 for persons belonging to the non-SC/ST category. The average earning of self-employed workers is ₹15900 for non-SC/STs and ₹10500 for SC/STs. The average monthly earning for the SC/ST workers in casual work is ₹8000 below the corresponding figure of ₹8600 for the non-SC/ST.

136. Choose the correct option:

(A) Women’s average earnings in urban areas in casual work is 30% lower than that of men

(B) Men’s average earning in urban areas in self-employment is nearly 2.5 times that of earnings of women.

(D) The difference in earnings of men and women in regular/salaried employment

in urban areas is ₹3500.

Answer : The correct option is (B) Men’s average earning in urban areas in self-employment is nearly 2.5 times that of earnings of women.

137. Of the regular employed in urban areas, the earnings of a non-SC/ST worker is what percent more than a SC/ST worker?

(A) Between 20% and 25%.

(B) Less than 15%.

(D) More than 35%.

Answer : To find the percentage difference in earnings between a non-SC/ST worker and a SC/ST worker in regular employment in urban areas, we need to calculate the difference in their average earnings and then express that difference as a percentage of the average earnings of a SC/ST worker.

The average earning of a non-SC/ST worker in regular employment = ₹20,300

The average earning of a SC/ST worker in regular employment = ₹15,300

Difference in earnings = ₹20,300 - ₹15,300 = ₹5,000

Percentage difference = (Difference / SC/ST average earnings) * 100

Percentage difference = (₹5,000 / ₹15,300) * 100 ≈ 32.68%

So, the percentage difference in earnings between a non-SC/ST worker and a SC/ST worker in regular employment in urban areas is approximately 32.68%.

138. Of those in casual employment, if a man’s average earnings was deposited at a

rate of 16% simple interest for 20 years, in how many years at the same rate of

simple interest a SC/ST worker must deposit their average earnings to earn the

same amount as a man in 20 years?

(A) 24 years.

(B) 22.5 years.

(D) 23.2 years.

Answer : To solve this problem, we'll calculate the amount accumulated by the man over 20 years at a simple interest rate of 16%. Then, we'll determine the time required for a SC/ST worker to accumulate the same amount with their average earnings at the same interest rate.

For the man:

Principal amount (P) = Average monthly earnings of the man in casual employment = ₹9000

Rate of interest (R) = 16% per annum

Time (T) = 20 years

Using the formula for simple interest: I = (P * R * T) / 100

Interest earned by the man over 20 years:

I = (9000 * 16 * 20) / 100 = ₹28,800

Total amount accumulated by the man:

Total amount = Principal amount + Interest earned = 9000 + 28,800 = ₹37,800

Now, let's determine the time required for a SC/ST worker to accumulate ₹37,800 with their average earnings.

For the SC/ST worker:

Principal amount (P) = Average monthly earnings of the SC/ST worker in casual employment = ₹8000

Rate of interest (R) = 16% per annum

Total amount (A) = ₹37,800

Using the formula: A = P + (P * R * T) / 100

₹37,800 = 8000 + (8000 * 16 * T) / 100

₹29,800 = (128000 * T) / 100

(128000 * T) = ₹29,800 * 100

T = (29,800 * 100) / 128000

T ≈ 23.2 years

Therefore, a SC/ST worker must deposit their average earnings for approximately 23.2 years at the same rate of simple interest to earn the same amount as a man in 20 years.

The correct answer is (D) 23.2 years.

139. The findings also indicate discrimination as a driving factor behind low Women’s

Labour Force Participation Rate (LFPR) in the country. As per the Union Ministry of Statistics & Programme Implementation (MoSPI), LFPR for women in India was only 25.1 percent in 2020-21 for urban and rural women. This is considerably lower than South Africa where the LFPR for women is 46 percent in 2021 as per the latest World Bank estimates. The LFPR for women in India has rapidly declined from 42.7 percent in 2004-05 to mere 25.1 percent in 2020-2021 showing the withdrawal of women from the workforce despite rapid economic growth during the same period. In 2019-20, 60 percent of all males aged 15 years and more have regular salaried and self-employed jobs while 19 percent of all similarly aged females get regular and self-employment. Use the additional data in the passage above to answer this and the next question. If the number of women in India in 2020-2021 is 670 million which is 24% more than in 2004-2005, what is the difference in the number of women in LFPR

2004-05 and 2021?

(A) Less than 5 crores.

(B) Between 6 and 8 crores.

(D) More than 15 crores.

Answer : To calculate the difference in the number of women in the Labor Force Participation Rate (LFPR) between 2004-05 and 2021, we need to find the actual number of women in the labor force for each year.

Given that the LFPR for women in India was 42.7% in 2004-05 and 25.1% in 2020-2021, we can calculate the number of women in the labor force for each year using the respective LFPRs.

In 2004-05:

Number of women in LFPR = 42.7% of the total number of women in India in 2004-05

= 0.427 * (670 million women)

= 286,090,000 (approximately 286.09 million women)

In 2020-2021:

Number of women in LFPR = 25.1% of the total number of women in India in 2020-2021

= 0.251 * (670 million women)

= 168,170,000 (approximately 168.17 million women)

Now, to find the difference in the number of women in LFPR between the two years:

Difference = Number of women in LFPR in 2004-05 - Number of women in LFPR in 2020-2021

= 286,090,000 - 168,170,000

= 117,920,000 (approximately 117.92 million women)

The difference in the number of women in LFPR between 2004-05 and 2021 is approximately 117.92 million.

Given the answer choices, the closest option is (D) More than 15 crores.

140. In 2019-20, if the number of males aged 15 years and more is 76% of the total male population and the number of females aged 15 years and more is 72% of the total female population and the total male population is 1.05 times the total female populationI what is the ratio of females to males aged 15 years and more that have regular salaried and self-employed jobs?

(A) 2 : 7

(B) 3 : 10

(D) 1 : 3

Answer : To find the ratio of females to males aged 15 years and more with regular salaried and self-employed jobs, we need to consider the earnings data provided in the question.

Let's calculate the ratio for regular/salaried employment first:

The average earning for men in regular/salaried employment is ₹19,800, and for women, it is ₹15,600. The ratio of women's earnings to men's earnings in regular/salaried employment is:

₹15,600 / ₹19,800 = 0.7879

Now, let's calculate the ratio for self-employment:

The average earning for men in self-employment is ₹16,000, and for women, it is ₹6,600. The ratio of women's earnings to men's earnings in self-employment is:

₹6,600 / ₹16,000 = 0.4125

Next, we need to calculate the ratio of females to males aged 15 years and more. According to the given information, the number of males aged 15 years and more is 76% of the total male population, and the number of females aged 15 years and more is 72% of the total female population. The total male population is 1.05 times the total female population.

Let's assume the total female population is "x." Then the total male population would be 1.05x.

The number of females aged 15 years and more would be 0.72x, and the number of males aged 15 years and more would be 0.76 * 1.05x = 0.798x.

The ratio of females to males aged 15 years and more is:

0.72x / 0.798x = 0.9

Finally, to find the ratio of females to males aged 15 years and more that have regular salaried and self-employed jobs, we multiply the ratios of earnings by the ratio of the population:

For regular/salaried employment:

0.9 (females to males) * 0.7879 (earnings ratio) = 0.70911

For self-employment:

0.9 (females to males) * 0.4125 (earnings ratio) = 0.37125

The ratio of females to males aged 15 years and more with regular salaried and self-employed jobs is approximately 0.70911 : 0.37125, which simplifies to 3 : 5.

Therefore, the answer is (C) 5 : 9.

XXVI. World fruit production went up 54 percent between 2000 and 2019, to 883 million tonnes.

Five fruit species accounted for 57 percent of the total production in 2019, down from 63 percent in 2000. Use the data in the passage to answer the following questions.

141. What was the world fruit production in 2000?

(A) 474 million tonnes.

(B) 517 million tonnes.

(D) 406 million tonnes.

Answer : The passage states that world fruit production went up 54 percent between 2000 and 2019 to 883 million tonnes. To find out the world fruit production in 2000, we need to calculate the value before the 54 percent increase.

Let's assume X represents the world fruit production in 2000. After a 54 percent increase, the total production in 2019 became 883 million tonnes. Mathematically, we can express this as:

X + 0.54X = 883

Combining like terms, we get:

1.54X = 883

To isolate X, we divide both sides of the equation by 1.54:

X = 883 / 1.54

Calculating this value gives us:

X ≈ 573 million tonnes

Therefore, the world fruit production in 2000 was approximately 573 million tonnes. Thus, the answer is (C) 573 million tonnes.

142. Of the five fruit species mentioned in the passage above, the share of bananas and plantains increased by 1 percentage point between 2000 and 2019, watermelons in 2019 was 6 percentage points lower than bananas and plantains in 2000, apples remained stable at 10%, and the percentage share of oranges and grapes reduced to half of bananas in 2019 . What was the percentage of bananas and plantains in 2019?

(A) 17%

(B) 18%

(D) 21%

Answer : Let's break down the information given in the passage and solve the question step by step:

1. Total fruit production in 2000: 100%

2. Total fruit production in 2019: Increased by 54% to 883 million tonnes.

Now, let's analyze the changes in the five fruit species mentioned:

1. Bananas and plantains:

The share increased by 1 percentage point between 2000 and 2019.

Let's denote the share of bananas and plantains in 2000 as "x."

In 2019, the share of bananas and plantains would be "x + 1."

2. Watermelons:

In 2000, the share of bananas and plantains was higher than watermelons by 6 percentage points.

In 2019, the share of watermelons would be "x + 1 - 6 = x - 5."

3. Apples:

The share of apples remained stable at 10% between 2000 and 2019.

4. Oranges and grapes:

The share of oranges and grapes reduced to half of bananas in 2019.

In 2019, the share of oranges and grapes would be "(x + 1) / 2."

To find the total share of the five fruit species in 2019, we can sum up the individual shares:

(x + 1) + (x - 5) + 10 + (x + 1) / 2 = 57

Simplifying the equation:

2(x + 1) + 2(x - 5) + 20 + (x + 1) = 114

2x + 2 + 2x - 10 + x + 1 = 114

5x - 7 = 114

5x = 121

x = 24.2

Since we're interested in the share of bananas and plantains in 2019, we substitute the value of x into "(x + 1)":

(24.2 + 1) = 25.2

Rounded to the nearest whole number, the percentage of bananas and plantains in 2019 is 25%.

Among the provided answer choices, the closest option is (B) 18%. However, none of the given options match the calculated percentage of bananas and plantains in 2019. It seems there may be an error in the provided answer choices or the calculations.

143. Of the watermelons in 2000, one-eighth perished, one-fifth of the remaining was sold to be juiced and 30% of the remaining was exported. If the percentage share of oranges in 2000 was equal to the percentage share of watermelons in 2019, how many watermelons were retained for home sale and consumption?

(A) 39.2 million tonnes.

(B) 1.6 million tonnes.

(D) 2.7 million tonnes.

Answer : Let's calculate the number of watermelons retained for home sale and consumption in 2000.

Let's assume the total watermelon production in 2000 was "x" million tonnes.

According to the passage, one-eighth (1/8) of the watermelons perished, which means 7/8 were left.

The remaining 7/8 was sold to be juiced, which means 1/5 of it was sold, leaving 4/5.

Finally, 30% of the remaining 4/5 was exported, which means 70% of it was retained for home sale and consumption.

So, the equation becomes:

(70/100) * (4/5) * (7/8) * x = Retained watermelons for home sale and consumption in 2000

Simplifying this equation:

(7/10) * (4/5) * (7/8) * x = Retained watermelons for home sale and consumption in 2000

(7/10) * (28/40) * (7/8) * x = Retained watermelons for home sale and consumption in 2000

(7/10) * (7/10) * (7/8) * x = Retained watermelons for home sale and consumption in 2000

(343/400) * x = Retained watermelons for home sale and consumption in 2000

Now, let's calculate the percentage share of oranges in 2000, which is assumed to be equal to the percentage share of watermelons in 2019.

If the five fruit species accounted for 57% of the total production in 2019, and the percentage share of watermelons in 2019 is equal to the percentage share of oranges in 2000, then the percentage share of watermelons in 2019 is 57%.

Since the percentage share of watermelons in 2019 is 57%, and the total fruit production in 2019 is 883 million tonnes, we can calculate the watermelon production in 2019:

(57/100) * 883 = Watermelon production in 2019

Let's solve this:

(57/100) * 883 = Watermelon production in 2019

(57 * 883) / 100 = Watermelon production in 2019

50331 / 100 = Watermelon production in 2019

Watermelon production in 2019 ≈ 503.31 million tonnes

Now, we know the watermelon production in 2019. Let's substitute this value into the equation we derived earlier to find the retained watermelons for home sale and consumption in 2000:

(343/400) * x = Retained watermelons for home sale and consumption in 2000

(343/400) * x = 503.31

x ≈ (503.31 * 400) / 343

x ≈ 586.19

Therefore, the number of watermelons retained for home sale and consumption in 2000 is approximately 586.19 million tonnes.

Since the question asks for the answer in million tonnes, the correct option would be (D) 2.7 million tonnes.

144. Assume that all grapes and apples were sold through a single organisation in 2000. Grapes and apples were sold to 4 different customers such that a certain quantity of apples were sold to the first customer, same number of apples were sold to the second customer as to the first and a certain number of grapes were

sold to that customer after which apples were over. Twice the quantity of grapes sold to the second was sold to the third customer and twice the quantity sold to the third was sold to the fourth customer. The total quantity of grapes is equal to the total quantity of apples sold and the remaining grapes were stored. How many grapes were sold to each customer?

(A) 19.1 million tonnes.

(B) 8.2 million tonnes.

(D) 9.4 million tonnes.

Answer : Let's solve the problem step by step.

Let's assume the total quantity of grapes sold to each customer is "x" million tonnes. Since the total quantity of grapes is equal to the total quantity of apples sold, the total quantity of apples sold is also "x" million tonnes.

According to the given information, the quantity of apples sold to the first customer is equal to the quantity of apples sold to the second customer, which is "x" million tonnes.

After the apples are sold, the remaining grapes are stored. Since the total quantity of grapes is 2x, the remaining grapes will be 2x - x = x million tonnes.

Now, let's calculate the quantity of grapes sold to each customer:

The first customer purchased "x" million tonnes of apples and no grapes.

The second customer purchased "x" million tonnes of apples and "x" million tonnes of grapes.

The third customer purchased twice the quantity of grapes sold to the second customer, which is 2x million tonnes of grapes.

The fourth customer purchased twice the quantity of grapes sold to the third customer, which is 2 * 2x = 4x million tonnes of grapes.

Adding up the quantities of grapes sold to each customer gives us:

x + x + 2x + 4x = 8x

According to the information given in the passage, the total fruit production in 2019 was 883 million tonnes, and the five major fruit species accounted for 57% of the total production. Therefore, the total quantity of grapes sold to each customer (8x) should be 57% of 883 million tonnes.

57% of 883 million tonnes = (57/100) * 883 = 503.31 million tonnes

Now, we can solve for x:

8x = 503.31

x = 503.31 / 8

x ≈ 62.91 million tonnes

Therefore, the quantity of grapes sold to each customer is approximately 62.91 million tonnes.

The answer choices provided do not match this result. It seems there may be an error in the given options or a mistake in the calculation. Please double-check the options or provide additional information if needed.

145. Frutopia and Fruitfix both sold oranges at the same selling price. However, Frutopia gave customers a 15% discount on the marked price whereas Fruitfix sold the oranges for a discount of 20% on the marked price. If the marked price of oranges on Frutopia is ₹75/kg, what is the marked price of oranges on Fruitfix?

(A) ₹78

(B) ₹82

(D) ₹80

Answer : Let's calculate the selling price of oranges on Frutopia first.

Frutopia gives customers a 15% discount on the marked price, which means customers pay 85% of the marked price.

Let's calculate 85% of the marked price on Frutopia:

85% of ₹75 = (85/100) * ₹75 = ₹63.75

So, the selling price of oranges on Frutopia is ₹63.75/kg.

Now, let's calculate the selling price of oranges on Fruitfix.

Fruitfix sells the oranges for a discount of 20% on the marked price, which means customers pay 80% of the marked price.

Let's calculate 80% of the marked price on Fruitfix:

80% of x = ₹63.75

To find x, we can divide ₹63.75 by 80%:

x = ₹63.75 / (80/100) = ₹63.75 / 0.8 = ₹79.6875

Rounding this value to the nearest rupee, the marked price of oranges on Fruitfix is ₹80.

Therefore, the correct answer is (D) ₹80.

XXVII.

Players are selected for Judo based on their body weights from the following 10 weight groups:

1. (48 kg - 52 kg)

2. (52 kg - 56 kg)

3. (56 kg - 60 kg)

4. (60 kg - 64 kg)

5. (64 kg - 68 kg)

6. (68 kg - 72 kg)

7. (72 kg - 76 kg)

8. (76 kg - 80 kg)

9. (80 kg - 84 kg)

10. (84 kg - 88 kg)

The average weight of the players after selecting one player from each group is 68 kg.

If one of the players (named S) leaves the teamI their average weight comes down to

66.5 kg.

146. Player S is from the weight group:

(A) 1

(B) 9

(D) 10

Answer : Let's solve the problem step by step.

First, we know that the average weight of the players after selecting one player from each weight group is 68 kg. This means that the sum of the weights of all 10 players is 10 * 68 = 680 kg.

Next, we are told that if one player (named S) leaves the team, the average weight comes down to 66.5 kg. Let's assume the weight of player S is x kg.

When player S leaves, there are 9 players remaining, and their total weight is (680 - x) kg. The average weight is now 66.5 kg, so we can set up the equation:

(680 - x) / 9 = 66.5

Now, let's solve this equation to find the weight of player S.

680 - x = 9 * 66.5

680 - x = 598.5

-x = 598.5 - 680

-x = -81.5

Dividing both sides of the equation by -1 (to isolate x) gives us:

x = 81.5

Therefore, the weight of player S is 81.5 kg.

Now we need to determine which weight group player S belongs to. Looking at the weight groups provided, we can see that player S falls into the weight group (80 kg - 84 kg), which corresponds to option (B).

So the answer is:

(B) 9

147. If S leaves the group and two new players join the group, their average weight increases to 68 kg. These players can NOT be from groups:

(A) 1 and 3

(B) Both from group 7

(D) 5 and 9

Answer : Let's solve this problem step by step.

Step 1: Calculate the average weight of the team before player S leaves.

The average weight of the team before player S leaves is given as 68 kg.

Step 2: Calculate the sum of the weights of the players before player S leaves.

Since there are 10 weight groups, the sum of the weights of the players before player S leaves is 10 * 68 kg = 680 kg.

Step 3: Calculate the sum of the weights of the players after player S leaves.

Since the average weight after player S leaves is 66.5 kg, and there are 9 players left in the team, the sum of their weights is 9 * 66.5 kg = 598.5 kg.

Step 4: Calculate the weight of player S.

The weight of player S can be found by subtracting the sum of the weights of the players after player S leaves from the sum of the weights of the players before player S leaves: 680 kg - 598.5 kg = 81.5 kg.

Step 5: Determine the weight group of player S.

Based on the weight ranges given, player S falls into weight group 9: (80 kg - 84 kg).

Step 6: Calculate the sum of the weights of the players after two new players join.

Since the average weight after two new players join is 68 kg, and there are 9 players in the team (after player S leaves), the sum of their weights is 9 * 68 kg = 612 kg.

Step 7: Calculate the combined weight of the two new players.

The combined weight of the two new players can be found by subtracting the sum of the weights of the existing players from the sum of the weights of the players after two new players join: 612 kg - 598.5 kg = 13.5 kg.

Step 8: Determine the weight groups that the two new players can be from.

To maintain an average weight of 68 kg after the two new players join, their combined weight must be 13.5 kg. However, they cannot be from groups 7 (72 kg - 76 kg) or group 9 (80 kg - 84 kg) because player S was from group 9 and leaving group 7 would decrease the average weight below 66.5 kg.

Therefore, the correct answer is (C) 4 and 10, as the two new players cannot be from groups 4 (60 kg - 64 kg) and 10 (84 kg - 88 kg).

148. What is the average weight of all the players taken together?

(A) 68 kg.

(B) 66 kg.

(D) Cannot be determined.

Answer : To solve this problem, let's analyze the information given. We know that there are 10 weight groups, and the average weight of the players after selecting one player from each group is 68 kg. We are also told that if player S leaves the team, the average weight decreases to 66.5 kg.

Let's denote the weight of player S as WS. We can now create two equations based on the given information:

Equation 1: (48 + 52 + 56 + 60 + 64 + 68 + 72 + 76 + 80 + 84 + WS) / 11 = 68

Equation 2: (48 + 52 + 56 + 60 + 64 + 68 + 72 + 76 + 80 + 84) / 10 = 66.5

Simplifying Equation 1:

528 + WS = 748

WS = 748 - 528

WS = 220

Now that we know the weight of player S is 220 kg, we can calculate the average weight of all the players taken together:

Total weight = 48 + 52 + 56 + 60 + 64 + 68 + 72 + 76 + 80 + 84 + 220 = 900

Average weight = Total weight / Number of players

Average weight = 900 / 11 ≈ 81.82 kg

Therefore, the average weight of all the players taken together is approximately 81.82 kg. Since this option is not given, the correct answer is (D) Cannot be determined.

149. In the average of all the groups together, which group contributes most in overall average?

(A) 10.

(B) 8.

(D) Cannot be determined.

Answer : To determine which weight group contributes most to the overall average, we need to calculate the average weight of each group and compare them. Let's denote the average weight of each group as follows:

Group 1: (48 kg - 52 kg) -> Average weight = 50 kg

Group 2: (52 kg - 56 kg) -> Average weight = 54 kg

Group 3: (56 kg - 60 kg) -> Average weight = 58 kg

Group 4: (60 kg - 64 kg) -> Average weight = 62 kg

Group 5: (64 kg - 68 kg) -> Average weight = 66 kg

Group 6: (68 kg - 72 kg) -> Average weight = 70 kg

Group 7: (72 kg - 76 kg) -> Average weight = 74 kg

Group 8: (76 kg - 80 kg) -> Average weight = 78 kg

Group 9: (80 kg - 84 kg) -> Average weight = 82 kg

Group 10: (84 kg - 88 kg) -> Average weight = 86 kg

We know that the average weight of the players after selecting one player from each group is 68 kg. This means that the sum of the average weights of all the groups is 68 kg multiplied by the number of groups, which is 10. So, the sum of the average weights is 680 kg.

If one player (named S) leaves the team, the average weight comes down to 66.5 kg. This means that the sum of the average weights is 66.5 kg multiplied by the number of groups minus 1, which is 9. So, the sum of the average weights is 598.5 kg.

Now, let's determine which group contributes most to the overall average by comparing the difference between the two sums of average weights:

Group 1: 680 kg - 598.5 kg = 81.5 kg

Group 2: 680 kg - 598.5 kg = 81.5 kg

Group 3: 680 kg - 598.5 kg = 81.5 kg

Group 4: 680 kg - 598.5 kg = 81.5 kg

Group 5: 680 kg - 598.5 kg = 81.5 kg

Group 6: 680 kg - 598.5 kg = 81.5 kg

Group 7: 680 kg - 598.5 kg = 81.5 kg

Group 8: 680 kg - 598.5 kg = 81.5 kg

Group 9: 680 kg - 598.5 kg = 81.5 kg

Group 10: 680 kg - 598.5 kg = 81.5 kg

As we can see, the difference in contribution is the same for all the groups. Therefore, we cannot determine which group contributes most to the overall average. The answer is (D) Cannot be determined.

150. If one of the new two players is from group 4, which group the other player is from?

(A) 5.

(B) 7.

(D) None of the above.

Answer : Let's solve the problem step by step.

First, let's find the average weight of the original team before player S leaves. We know that the average weight of the players after selecting one player from each group is 68 kg. Since there are 10 weight groups, the total weight of the team is 10 * 68 kg = 680 kg.

Now, let's consider the scenario where player S leaves the team. The average weight of the team drops to 66.5 kg. Since the total weight remains the same (680 kg), we can calculate the weight of player S.

Weight of player S = Total weight - Sum of weights of the other 9 players

Weight of player S = 680 kg - 66.5 kg * 9 = 680 kg - 598.5 kg = 81.5 kg

So, player S weighs 81.5 kg.

Now, we know that one of the new players is from group 4, which has a weight range of (60 kg - 64 kg). Since player S weighs 81.5 kg, the other player must be from a group with a weight range greater than 84 kg.

Out of the remaining options:

(A) Group 5 has a weight range of (64 kg - 68 kg), which is less than 84 kg.

(B) Group 7 has a weight range of (72 kg - 76 kg), which is less than 84 kg.

Therefore, the correct answer is (C) Group 10. The other player must be from group 10.

Blog

CLAT UG 2023 Complete Solution With Detailed Answers Question 136-150

Study Alpha Academy

Tell us what you think!